When it comes to IT administration tasks, extracting files from zipped archives can be a time-consuming and tedious process. As the amount of files grows, the task becomes increasingly difficult. Luckily, there is an easy way to automate the process of extracting files from zipped archives in a directory, including subdirectories, using a batch file or DOS command.
The first step is to create a batch file. This file will contain the command necessary to extract the files from each zip archive. The command needed is “extract”, so the batch file will look something like this:
for /r %%X in (*.zip) do extract %%X
This command will loop through all the zip files in the directory and its subdirectories, and extract the files from each one.
Once the batch file is created, the next step is to run it. This can be done by opening a command prompt, navigating to the directory containing the batch file, and typing “extract” followed by the name of the batch file. For example, if the batch file is named “extract.bat”, the command to run it would be “extract extract.bat”.
Alternatively, the batch file can be run from the command line without opening a command prompt. To do this, simply type the full path to the batch file. For example, if the batch file is located in the “C:\\files” directory, the command to run it would be “C:\\files\\extract.bat”.
Once the batch file has been run, the files from each zip archive in the directory, including subdirectories, will be extracted. The files will be placed in the same directory as the zip archive.
Using a batch file or DOS command to extract files from zipped archives in a directory, including subdirectories, is a quick and easy way to automate the process. It eliminates the need to manually extract the files from each zip archive, saving both time and effort.
